Board Thread:Fun and Games/@comment-4297047-20131228160328/@comment-4297047-20140104141117

You get Bigrandsuperiordeuteroexibang, $$F_{F_{F_{1}(F_{1}(2))}(F_{1}(2))}(F_{1}(2))!$$

I insert Grandtetraexibang, $$F_{F_{1}(4)}(4)!$$